Plz help me

y=-3/2x+6

Step-by-step explanation:

You can find the slope by taking two points on the graph, and making the one that occurs earlier in the graph (from left to right) the first point (x1, y1) and the one that occurs later in the graph the second point (x2, y2). The equation is m (or slope)=(y2-y1)/(x2-x1). I took the first two points in the table for this. m=(12-18)/-4-(-8)

the double negative on the bottom becomes an addition=> (12-18)/(-4+8)

the top simplifies to be -6 and the bottom simplifies to 4=>-6/4

this fraction can be reduced to -3/2, which is the slope of the graph.

Now, use point slope form (y-y1=m(x-x1)) to find the equation of the graph. Plug any coordinate on the graph in for x1 and y1 here. It should be correct as long as it is a point on the graph, but I am using the point (-8, 18) here.

=>y-18=-3/2(x-(-8))

the double negative in the parentheses becomes a positive=> y-18=-3/2(x+8)

distribute the -3/2 to every term in the parentheses=> y-18=-3/2x-12

add 18 to both sides, cancelling out the -18 on the left side of the equation=>y=-3/2x+6 (-12+18=6 to get 6 for b).

Therefore, the equation is y=-3/2x+6

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

you need to give us more information since we can't answer