What is the area of a trapezoid ABCD with bases AB and CD , if: AB=10cm, BC=DA=13cm, CD=20cm I’ll give brainliest to correct answer

180

Step-by-step explanation:

1. for the required area use the next formula:

where h is the height of the given trapezoid.

2. according to the attached scheme/picture the height is h=AH=BH₁

3. in ABH₁H:

AB║HH₁; AH║BH₁ and m(∠A)=m(∠B)=m(∠H)=m(∠H)=90°, then AB=H₁H=10 and CH=DH=(CD-AB)/2=(20-10)/2=5 cm.

4. in ΔADH:

m(∠H)=90°; AD=13 cm.; DH=5 cm., then AH=12 cm. But the height h is AH=12, then h=12.

5. after the substitution into the formula:

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

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step-by-step explanation:

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