Is there anyone who would be so kind and help explain how I solve this? What is the equation of the line that has a slope of 3 and goes through the point (-3,-5)?

Let's remember the equation of a line:

y = mx + b

m: slope (we know it's 3)

b: the y-intercept

So far, we have y = 3x + b, now we need to find b.

Replacing y and x for the given points (-3,-5):

-5 = 3*(-3) + b

-5 = -9 + b

b = -5 + 9

b = 4

The equation of the line that passes through the point (-3,-5) with a slope of 3 is y = 3x + 4Step-by-step explanation:

dwe

step-by-step explanation:

ewd

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!