Jim wants to make 2.7 quarts of a 60% alcohol solution by mixing together a 80% alcohol solution and a 20% alcohol solution. How much of each solution must Jim use?

1.8 quartz of 80% solution and

0.9 quarts of 20% solution.

Step-by-step explanation:

Given that:

Total alcohol solution to be made = 2.7 quarts of 60% solution

Alcohol concentration in first solution= 80%

Alcohol concentration in second solution = 20%

To find:

How much of each solution must Jim use?

Solution:

Let amount of first solution to be used = quartz

Total amount is given as = 2.7 quarts

So, amount of second solution to be used = (2.7 - ) quartz

As per question statement, we can write the following equation:

First solution, 80% solution to be used = 1.8 quartz

Second solution, 20% solution to be used = 2.7 - 1.8 = 0.9 quartz

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3