Faith wants to use the formula C(f) = 5/9 (f - 32) to convert degrees Fahrenheit, f, to degrees Celsius, C(f). If Faith calculated C (68), what would her result be?

Her results would be 20ºC.

Step-by-step explanation:

The c(f) transformation means that for a Fahrenheit temperature measure, we can realize the conversion to Celsius using the following formula.

c(f) = \frac{5}{9}*(f-32)c(f)=95∗(f−32)

In which f is the temperature measured in fahrenheit and c is the temperature measured in celsius.

If faith calculated c(68), what would her results be

She wants to realize the conversion of 68 fahrenheit to celsius. So

c(f) = \frac{5}{9}*(f-32)c(f)=95∗(f−32)

c(68) = \frac{5}{9}*(68-32) = 20c(68)=95∗(68−32)=20

Her results would be 20ºC.

the formula of a slope:

from a table we have

substitute:

the slope of f(x) is -1.

the graph of funcfion g(x) is a horizontal line. the slope of a horizontal line is equal 0. therefore the slope of g(x) is 0.

-1 < 0

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°