Solve for x.

3/7X+ 1/3x = 32

X = ?

3/7x+1/3x=32

We move all terms to the left:

3/7x+1/3x-(32)=0

Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R

Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R

We calculate fractions

9x/21x^2+7x/21x^2-32=0

We multiply all the terms by the denominator

9x+7x-32*21x^2=0

We add all the numbers together, and all the variables

16x-32*21x^2=0

Wy multiply elements

-672x^2+16x=0

a = -672; b = 16; c = 0;

Δ = b2-4ac

Δ = 162-4·(-672)·0

Δ = 256

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x1=−b−Δ√2ax2=−b+Δ√2a

Δ−−√=256−−−√=16

x1=−b−Δ√2a=−(16)−162∗−672=−32−1344=1/42

x2=−b+Δ√2a=−(16)+162∗−672=0−1344=0

step-by-step explanation: