A 42-inch piece of steel is cut into 3 pieces so that the 2nd piece is twice as long as the 1st piece, and the 3rd piece is 2 inches more than 5x the length of the first piece. Find the lenth of the pieces.

1st piece = Piece A = 5 inches

2nd piece = Piece B = 10 inches

Third Piece = Piece C = 27 inches

Step-by-step explanation:

A 42-inch piece of steel is cut into 3 pieces

Let the lengths be represented as:

1st piece = Piece A

2nd piece = Piece B

Third Piece = Piece C

Hence:

A + B + C = 42

The 2nd piece is twice as long as the 1st piece

B = 2A

The 3rd piece is 2 inches more than 5 times the length of the first piece.

C = 5A + 2

Hence: we substitute

A + B + C = 42 inches

A + 2A + 5A + 2 = 42 inches

8A = 42 - 2

8A = 40 inches

A = 40 inches/8

A = 5 inches

Solving for B

B = 2A

B = 2 × 5 inches

B = 10 inches

Solving for C

C = 5A + 2

C = 5 × 5 + 2

C = 25 + 2

C = 27 inches

Therefore, the lengths of the 3 pieces =

1st piece = Piece A = 5 inches

2nd piece = Piece B = 10 inches

Third Piece = Piece C = 27 inches

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