An auto weighing 2,500 pounds is on a street inclined at 10 with the horizontal. find the force necessary to prevent the car from rolling down the hill.

round your answer to the nearest whole number. do not use a space or decimal in your answer or it will be marked wrong.

13892 lb-ft/sec^2

Step-by-step explanation:

Given that An auto weighing 2,500 pounds is on a street inclined at 10 with the horizontal.

Here acceleration due to gravity is the pulling factor against which the car should be stopped from rolling down the hill.

Weight of the car =2500 pounds

Vertical component of gravity = 32cos (90-10)=32sin 10 = 32(0.1736)

Force required = mass x acceleration

=2500x0.1736x32

=13892 lb ft/sec^2

x = 10.1

step-by-step explanation:

all of the angles of a tirangle add up to 180º

180 - 65 = 115 (since we already know the value of one angle)

(2x + 7) + (8x + 7) = 115

(combins like terms) 10x + 14 = 115

(isolate the variable subtract 14 from both sides): 10x = 101

(find the variable divide both sides by 10): x = 101/10

x = 10.1

10

step-by-step explanation:

7+3=10