Mathematics, 07.12.2020 22:20, gabrielaperezcz
The angle of elevation of the top of a building from the foot of a tower is 70° and the angle of elevation of the top of the tower from the foot of the building is 40°. Find the height of the building if the tower is 50 m tall.
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Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .
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The angle of elevation of the top of a building from the foot of a tower is 70° and the angle of ele...
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