Can someone please help me with the question. Divide using LOND DIVISION:
(4x^4-5x^2+2x-11)/(2x+3)
a. 2x^3-3x^2+2x+4+-23/2x+3
b. 2x^3-3x+2x-2+-5/2x+3
c. 2x^3-3x^2-2x+2+5/2x+3
d. none of these

D (none of these)

Step-by-step explanation:

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

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