If BTS=GHD BS=25 TS=14 BT=31 GD=4x-11 S=56 B=21 and H=(7y+5) find the values of x and y

Given:

Consider the completer question is "If ∆BTS≅∆GHD, BS=25, TS=14, BT=31, GD=4x-11, m∠S=56, m∠B=21 and m∠H=(7y+5), find the values of x and y.

To find:

The values of x and y.

Solution:

We have,

      (Given)

                      (CPCTC)

Divide both sides by 4.

In ∆BTS,

   (Angle sum property)

Now,

           (CPCTC)

Divide both sides by 7.

Therefore, the value of x is 9 and value of y is 14.

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step-by-step explanation:

any options?

step-by-step explanation: