Describe how to evaluate the expression 3^2 + (21 - 9) X 6÷2. Can someone help me out, please? I'm having trouble, and my teacher isn't responding to my messages.

Step-by-step explanation:

Given the expression

Follow the PEMDAS order of operations

calculate within parentheses  

calculate exponents  

Multiply and divide (left to right)

Add and subtract (left to right)  

Thus,

answer: true

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v