Approximating slopes of tangent lines using the process shown last week for the function f(x) =3-x2 at the point (2, -1). Using a straightedge, draw a tangent line as accurately as possible at
the point (2, -1). Then draw a secant line through the points (2, -1) and (3, -6). We will refer to that as the right secant line. Draw another secant line, this time through the points (1, 2) and (2, -1). This is the left secant line. Answer the following questions.
2. What is the slope of the right secant line?

9514 1404 393

  -5

Step-by-step explanation:

The right secant line has a "rise" of -6-(-1) = -5 for a "run" of 3-2 = 1. The slope is the ratio ...

  m = rise/run = -5/1 = -5

The slope of the right secant line is -5.

hi, i am not sure about this one but i think its d,

hope this !

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.