Suppose 45% of the population has a college degree. If a random sample of size 662 is selected, what is the probability that the proportion of persons with a college degree will differ from the population proportion by more than 3%? Round your answer to four decimal places.

0.0604

Step-by-step explanation:

Given that:

Population proportion (p) = 45% = 0.45

Sample size (n) = 662

1 - p = 1-0.45 = 0.55

P - phat > 0.03

Standard deviation = sqrt((p(1-p))/n)

Using the relation :

P(Z > p - phat / sqrt((p(1-p))/n))

sqrt((p(1-p))/n) = Sqrt((0.45(0.55)/662) = 0.01933

P(Z > 0.03 / 0.0193356) = P(Z > 1.5515)

P(Z > 1.5515) = 0.0604 (Z probability calculator)

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13