If th ere are 10,000 stu dents enrolled in the college an d the institution is funded at the rate of $300 per student unit. At the 95 % confidence level, estimate the interval th at covers the total funding of the college . for full credit, round the answer to TWO decimal places!

Complete question :

A college is funded depending on the mean number of credit units a student takes. A survey involving 16 students yielded the mean number 12 units with a standard deviation 3 units. Assume normal population

If th ere are 10,000 stu dents enrolled in the college an d the institution is funded at the rate of $300 per student unit. At the 95 % confidence level, estimate the interval th at covers the total funding of the college . for full credit, round the answer to TWO decimal places!

(35823600 , 36176400)

Step-by-step explanation:

Mean number of units = 12

Standard deviation = 3

Number of samples (n) = 10000

Fund rate = 300

Mean = 10000 * 300 * 12 = 36000000

Standard deviation = 10000^0.5 * 300 * 3 = 90000

Fir 95% C. I

Z0.05 = 1.96

Interval = mean ± 1.96 * SE

(36000000 - 1.96*90000) ; (36000000 + 1.96*90000)

(35823600 , 36176400)

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*