what is 7h^5j^3k^2-8h^5j^3
IDC is you look it up but I need the step by step
pls do not mess around. if you don't know how to do it step by step. then pls don't just get the points. bc its not okay if you do.

Merry christmas srry

Step-by-step explanation:

Factored: h ^5  j ^3 ( 7 k ^2 − 8 )

GCF is h^5 j^3

Step-by-step explanation:

I got this because

(7h^5j^3k^2)-(8h^5j^3)

both sides have h and j  so

(7h^5j^3k^2)-(8h^5j^3), you take off h^5 from both

h^5 ((7 j^3k^2)-(8 j^3)), then take off j^3 from both sides

h^5 j^3(7k^2 - 8), and it

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.