Suppose a varies directly as b and inversely as c. Find b when a = 5 and 4, if b = 12 when C3 and a = 96

The value of b is 5/6

Step-by-step explanation:

The relationship stated as "a varies directly as b and inversely as c" can be written as:

Where k is the constant of proportionality. We need to find its value by plugging in the given condition: b=12 when c=3 and a=96:

Solving for k:

The relation is now written as:

Now we find the value of b when a=5 and c=4. Solving for b:

The value of b is 5/6

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

step-by-step explanation:

it will be a cylinder. with a diameter of 8 and 4 single pieces high