Some marbles in a bag are red and the rest are blue. If one red marble is removed, then one-seventh of the remaining marbles are red. If two blue marbles are removed
instead of one red, then one-fifth of the remaining marbles are red. How many
marbles were in the bag original

Pls give EXPLANATION

22

Step-by-step explanation:

Let r be red and b be blue

1/7(r-1+b)=r-1

1/5(r+b-2)=r

r-1+b=7(r-1)

r+b-2=5r

r-1+b=7r-7

1=7r-7-5r

8=2r

r=4

1/5(4+b-2)=4

2+b=20

b=18

18+4=22

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

susie has 7 apples