The diameter of a cylindrical construction pipe is 4 ft. If the pipe is 19 ft long, what is its volume? Use the value 3.14 for it, and round your answer to the nearest whole number.
Be sure to include the correct unit in your answer.
4 ft
O
19 ft

The volume of the pipe is 239 ft³

Step-by-step explanation:

The rule of the volume of a cylinder is V = π r² h, where

∵ The diameter of a cylindrical construction pipe is 4 ft

∵ The radius is half the diameter

∴ r = × 4 = 2 ft

∵ The pipe is 19 ft long

∴ h = 19 ft

∵ π = 3.14

→ Substitute them in the rule of the volume

∴ V = 3.14(2)²(19)

∴ V = 238.64 ft³

→ Round it to the nearest whole number

∴ V = 239 ft³

∴ The volume of the pipe is 239 ft³

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1