Suppose you roll two six-sided dice, one red and one blue. Each is labeled 1 through 6. What is the probability that you roll a two on the blue dye and the sum of both dice is greater than 4

 1/9

Work Shown:

If the blue die shows a "2", then the red die must take on the values from the set {3, 4, 5, 6} in order for the sum of both dice to be larger than 4.

2+3 = 5

2+4 = 6

2+5 = 7

2+6 = 8

There are 6*6 = 36 total ways to roll two dice and exactly 4 ways to get the conditions stated above. The probability of getting a sum greater than 4 is 4/36 = 1/9.

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.

If there are four friends then each would get, 1.25 or 1 1/4. so this is how i solved 5 ÷ 4 = 1.25 . hope this ; )