What will be the location of T′ in the image trapezoid S′T′U′V′? (18, −2) (18, 2) (15, −2) (15, 2)

(18,2)

Step-by-step explanation:

Let's start by determining the transformation of Rectangle J′K′L′M′

We can look at L.

In the original rectangle, L is at (-4,-2)

In the transformation, L' is at (9,-5)

|-4-9|=|-13|=13

|-2-(-5)|=|-2+5|=3

So the transformation is 13 units right and 3 units down.

In trapezoid STUV, the coordinates of T are are (5,5)  

We need to move it 13 units left and 3 units down.

This means we add 13 to the x coordinate and subtract 3 from the y coordinate.

5+13=18

5-3=2

The location of T' will be (18,2)

ANSWER CREDIT: anna2023147

(I DID NOT COME UP WITH THIS RESPONSE)

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic