In the prime factorization of 109!, what is the exponent of 3? (Reminder: The number n! is the product of the integers from 1 to n. For example, 5!=5* 4*3*2*1= 120$.)

53 is the exponent

Step-by-step explanation:

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

if you are looking for the unit rate then the answer would be 9 because unit rate is distance divided by time.

step-by-step explanation: