Please help me with this question! Thank you in advance. -The submarine started at 275 feet below sea level

-After one hour, the submarine is 325.8 feet below sea level. How many feet did it dive?

-After two hours, the submarine dives another 23 feet deeper.

-On hour three, the submarine descended the average of dives from hour one and two.

-Fill in chart below using the information above. Sea level is considered 0 feet.

Step-by-step explanation:

1. if the sub is at 325.8 at it was originally at 275 you have to put the numbers in absolute value. so 325.8 - 275=50.8

the sub went down -50.8 feet to get to 325.8

if the diver dives another 23 feet you have to put the numbers in absolute value and add 325.8 + 23= -348.8 feet underwater

on hour 3 it says that it descends an average of how much he went down in the first 2 hours witch is -73.8

i got -73.8 by adding hours one and two

then you add hour 3 by -348.8  

sine

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v