Mathematics, 04.12.2020 16:30, carlosluiscontrerasp
Stephanie gets an average of 11 calls during her 8 hour work day. What is the probability that Stephanie will get more than 4 calls in a 2 hour portion of her work day
Answers: 2
![P[X=k] = \dfrac{(\lambda t)^k\times e^{-\lambda t}}{k!} \ \ \ where; k = 0,1,2 ...](/tpl/images/0949/7298/6c5ef.png)
![=1 - [ P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) ]](/tpl/images/0949/7298/92a99.png)
![= 1 - \bigg [ \dfrac{(\dfrac{11}{4})^0 \times e^{-11/4}}{0!}+\dfrac{(\dfrac{11}{4})^1 \times e^{-11/4}}{1!}+ \dfrac{(\dfrac{11}{4})^2 \times e^{-11/4}}{2!}+ \dfrac{(\dfrac{11}{4})^3 \times e^{-11/4}}{3!}+ \dfrac{(\dfrac{11}{4})^4 \times e^{-11/4}}{4!} \bigg ]](/tpl/images/0949/7298/d2128.png)
![= 1 - [ 1 + 2.75 + 3.78125 + 3.466145833 + 2.3829] \ e^{-11/4}](/tpl/images/0949/7298/403fe.png)
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Stephanie gets an average of 11 calls during her 8 hour work day. What is the probability that Steph...
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