The equation d = 2t^ gives the distance from the start point of a toy boat that starts at rest and accelerates at 4 cm/s2. The equation d = 10t - 8 gives the distance from the start point of a second boat that starts at rest 8 cm behind the first boat and travels at a constant rate of 10 cm/s. a) By setting the equations equal to each other, you can determine when the cars are the same distance from the start point: 2t2 = 10t - 8. Rewrite the equation so it is equal to 0 on the right hand side of the equation.
b) Factor the expression on the left side of the equation.
c) boats are the same distance from the start point at t = 1 and t = 4. Explain how the factors you found in part b were used to find these two times.

the answer is 4.8 units on e2020.

2 & 7

step-by-step explanation:

he climbs 300 ft/hr at a constant rate. the peak is at 1,500 ft.

when going up, he reaches 600 ft in 2 hours. remember, that he is going in a constant rate. divide 600 with 300:

600/300 = 2

assuming that he takes the same route back (meaning that it's a 1500 ft route back, you can solve.

note also that you are solving when he gets back to 600 ft after he reaches the peak.

first, find the amount of hours it takes to get up the peak. divide the total amount (1500), with the ft/her (300) to get the amount of hours (x):

1500/300 = x

x = 5

it takes jamie 5 hours to get up. now, he is returning down, and reaches 600 (his current destination). remember that he climbs at a constant 300 ft/hr. divide 600 with 300:

600/300 = x

x = 2

now add the two numbers together.

x = 5 + 2 = 7

jamie takes 7 hours to go up the mountain and reach his current position when descending.

(total amount/constant rate) = (time).

remember that it is a constant rate, so in total, when he gets back down the mountain, it will take the same amount of time as when he goes up. the total amount for the round trip is: 5 + 5 = 10.

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