Draw the image of ABC△ under a translation by 5 units to the left.

Since you don't have a picture to go with this, I'll try to explain it the best I can. Each point in the shape you have to translate will move to the left 5 units. We would use (x, y) to figure out how to move it. Whatever number is in the x place in (x, y) will be decreased by 5. For example, if there was a point on (6, 3) and I had to translate it 5 units left, I would just do 6 - 5 and my answer would be (1, 3). Then you can do that for each point.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.