Perform the indicated operations, and designate answer using the
listing methods
Let u = {1,2,3,4,5,6,7}, L={1,3,5,73 M = { 1, 2,3}
N={2,3,4,5,6}
(Mn Ľ)'UN'

{1,3,4,5,6,7}

Step-by-step explanation:

Here , U represents the universal set

L’ = {2,4,6}

L’ is what we have in the universal set but not present in set L

(m n L’)

This is the set that contains the elements that are present in both set ONLY

So this is;

{2}

(M n L’)’ = {1,3,4,5,6,7}

N’ = {1,7}

So the union of both would be;

= {1,3,4,5,6,7}

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.