A golf ball is projected upward from ground level at an initial velocity of 112 ft/sec. The height of a projectile can be modeled by s(t) = – 16t^2 + v_0t + s_0

, where t is time in seconds, s_0 is the initial height in feet, and v_0 is the initial velocity in ft/sec.
How high will the ball be after 2seconds? When will the ball reach the ground?

answer for #1 is c

answer for #2 is d

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you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5

answer: 8

step-by-step explanation: if you add the possibilities 5 different flavor and 3 different sizes 5+3=8