Recent test scores on the Law School Admission Test (LSAT) are normally distributed with a mean of 162.4 and a standard deviation of 15.9. What is the probability that the mean of 8 randomly selected scores is less than 161?

0.40166

Step-by-step explanation:

When given random number of samples, we solve using the z score formula:

z = (x-μ)/σ/√n where

x is the raw score= 161

μ is the population mean = 162.4

σ is the population standard deviation = 15.9

n is random number of samples = 8

Hence,

z = 161 - 162.4/15.9/√8

z =-0.24904

Probability value from Z-Table:

P(x<161) = 0.40166

The probability that the mean of 8 randomly selected scores is less than 161 is 0.40166

g(x) is the negative form of f(x)? because whenever its the negative form it reflects its self over the x axis. idk if this is right though.

step-by-step explanation:

i think the answer is seven, for if i'm being useless °ω°

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