Anumber x is no more than 9 units away from 8. write and solve an absolute-value inequality to show the range of possible values of x.
|x − 8| ≤ 9
−1 ≤ x ≤ 17
|x + 8| ≤ 9
−17 ≤ x ≤ 1
|x − 9| ≤ 8
1 ≤ x ≤ 17
|x + 9| ≤ 8
−17 ≤ x ≤ −1

Option A is right

Step-by-step explanation:

Given that a number x is no more than 9 units away from 8

This implies that number can be either larger than 8 by less than 9 units or smaller than 8 by less than 9 units.

Difference between x and 8 is at most 9.

We represent in absolute value as

Hence option A is right

i need points

step-by-step explanation:

sorry bubs

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: