A particular type of cell doubles in number every hour. Which function can be used to find the number of cells present at the end of h hours if there are initially 4 of these cells?

The function would be

.This is in the general form

, where a is the initial value, b is the rate it increases by, and x is the amount of time.  For our function, the initial value is 4 and the rate it increases by is 2.

Step-by-step explanation:

The function would be

.This is in the general form

, where a is the initial value, b is the rate it increases by, and x is the amount of time.  For our function, the initial value is 4 and the rate it increases by is 2.

Step-by-step explanation:

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation

25.3

step-by-step explanation:

1st step

add 3+6

=9

multipy 9*3

=37