Suppose that prices of recently sold homes in one neighborhood have a mean of $265,000 with a standard deviation of $9300. Using chebyshev's theorem, state the range in which at least 88.9%of the data will reside

Range  = (237100, 292900)

Step-by-step explanation:

Using Chebyshevs Inequality:

Thus, 88.9% of the population is within 3 standard deviation of the mean with the Range = μ  ±  kσ

where;

μ = 265000

σ = 9300

Range = 265000  ±  3(9300)

Range = 265000  ± 27900

Range =   (265000 - 27900, 265000 + 27900)

Range  = (237100, 292900)

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25