Rick’s scores in his last 15 rounds of golf are 72, 80, 75, 84, 78, 72, 75, 68, 81, 74, 79, 70, 77, 83, and 72. If he scores an 80 on each of the next three rounds, which measure of center would increase more, the mean or median?

The median increased more

Step-by-step explanation:

Given that:

Scores on last 15 :

72, 80, 75, 84, 78, 72, 75, 68, 81, 74, 79, 70, 77, 83, 72

Obtaining the range, mean, median and mode from the data above :

Rearranged data:

68, 70, 72, 72, 72, 74, 75, 75, 77, 78, 79, 80, 81, 83, 84

Range = 84 - 64 = 16

Mode = 72 - frequency of 3)

Mean = ΣX / n where n = sample size

Mean = 1140 / 15 = 76

Median = 0.5(n+1)th term = 0.5(16)th term =

8th term = 75

A score of 80 on each of next 3 rounds :

72, 80, 75, 84, 78, 72, 75, 68, 81, 74, 79, 70, 77, 83, 72, 80, 80, 80

Rearranged data:

68, 70, 72, 72, 72, 74, 75, 75, 77, 78, 79, 80, 80, 80, 80, 81, 83, 84

Range = 84 - 68 = 16

Mean = ΣX / n where n = sample size

Mean = 1380 / 18 = 76.67

Median =0.5(n+1)th term = 0.5(19)th term =

9.5 = (9th term +. 10th term) / 2 = (77 +78) / 2 = 77.5

answer: sorry i can't you.

step-by-step explanation:

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.