A farmer is going to divide her 40 acre farm between two crops. Seed for crop A costs $15 per acre. Seed for crop B costs $30 per acre. The farmer can spend at most $900 on seed. If crop B brings in a profit of $50 per acre, and crop A brings in a profit of $110 per acre, how many acres of each crop should the farmer plant to maximize her profit? acres of crop A acres of crop B

The answer is below

Step-by-step explanation:

Let x represent the number of acre on which crop A is farmed and B represent the number of acre crop B is farmed.

Therefore:

Since there is a total of 40 acre farm, hence:

x + y = 40        (1)

The farmer can spend at most $900 on seed, crop A seed cost $15 and crop B seed cost $50, hence:

15x + 50y ≤ 900   (2)

Her profit is given as:

Profit = 50x + 110y

From the geogebra plot, the point that maximizes the profit is at (60, 0)

Therefore the maximum profit = 50(60) + 110(0) = $3000

i could probably can you me with a question of mine?

step-by-step explanation:

the height of the surface increases from the center out to the sides of the road.

step-by-step explanation:

as we move out we move away from the x-axis.

and as mentioned in the problem statement that height of a road increases when we move away from the center x.

hence proved that 3rd option

the height of the surface increases from the center out to the sides of the road.

is the correct option.