Mathematics, 03.12.2020 17:00, jadahilbun01
Three students Tahat, Promi and Kabi, Appeared at an examination. Promi secured 11 marks less than Tahat, 5 marks more than kabi and again. Tahat's marks were 75% of the sum of Promi and Kabi's marks. Find out their individual marks
Answers: 2
Mathematics, 22.06.2019 01:00, SpeechlessZzz9920
For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius and height 2r minus the volume of two cones, each with a radius and height of r. a cross section of the sphere is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is the volume of the cylinder with radius r and height 2r is and the volume of each cone with radius r and height r is 1/3 pie r^3. so the volume of the cylinder minus the two cones is therefore, the volume of the cylinder is 4/3pie r^3 by cavalieri's principle. (fill in options are: r/2- r- 2r- an annulus- a circle -1/3pier^3- 2/3pier^3- 4/3pier^3- 5/3pier^3- 2pier^3- 4pier^3)
Answers: 3
Mathematics, 22.06.2019 01:30, diamondgray2003
Quadrilateral efgh was dilated with the origin as the center of dilation to create quadrilateral e'f'g'h'. the quadrilateral was dilated using a scale factor of 2.5. the lengths of the sides of quadrilateral efgh are given. what is the length of side f'g'?
Answers: 1
Mathematics, 22.06.2019 04:30, xxtonixwilsonxx
Solve the following system algebraically. y = x2 – 9x + 18 y = x – 3 a. (3,1) and (5,3) b. (3,0) and ( 4,2) c. (–4,5) and (7,–10) d. (7,4) and (3,0)
Answers: 3
Three students Tahat, Promi and Kabi, Appeared at an examination. Promi secured 11 marks less than T...
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