The temperature fell from 0 Degrees Fahrenheit to 15 and one-half Degrees Fahrenheit below 0 in 5 and three-fourths hours. Wen tried to find the change in temperature per hour. Her work is shown below. Negative 15 and one-half divided by 5 and three-fourths = negative StartFraction 31 over 2 EndFraction divided by StartFraction 23 over 4 EndFraction = negative StartFraction 31 over 2 EndFraction times StartFraction 23 over 4 EndFraction = Negative StartFraction 713 over 8 EndFraction When she checked the answer by estimating, it did not make sense. What error did Wen make? Wen incorrectly converted a mixed number to an improper fraction. Wen added the numerators and denominators instead of multiplying. Wen did not take the reciprocal of the divisor. Wen did not change the division problem to multiplication.

Data on oxide thickness of semiconductors are as follows: 426 432 418 418 421 436 418 408 431 435 423 426 411 434 435 432 411 426 407 439 422 426 412 416 consider this data as a sample of the population. (a) calculate a point estimate of the mean oxide thickness for all wafers in the population. (round your answer to 3 decimal places.) (b) calculate a point estimate of the standard deviation of oxide thickness for all wafers in the population. (round your answer to 2 decimal places.) (c) calculate the standard error of the point estimate from part (a). (round your answer to 2 decimal places.) (d) calculate a point estimate of the median oxide thickness for all wafers in the population. (express your answer to 1 decimal places.) (e) calculate a point estimate of the proportion of wafers in the population that have oxide thickness greater than 430 angstrom. (round your answer to 4 decimal places.)