A hollow shaft has an outside diameter of 6.0cm and an inside diameter of 4.0cm. The cross-sectional area of the shaft is:
Select one:
O a. 1571 mm sa
O b. 6283 mm sa
O c. 628 mm sa
O d. 1257 mm sa
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5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116