Help me again. i need help. thx 4 helping

16 square units

Step-by-step explanation:

The formula for the area of a right triangle is ab/2 (a and b both being legs).

First, we find the legs' length which is MK and JK.

Since both points J and K are on the same y level, we look at the X coordinates and see how far apart they are.

Since both points M and K are on the same x level, we look at the Y coordinate.

M is 4 points away from K, so the leg MK is 4 units long.

J is 8 points away from K, so the leg JK is 8 units long.

Plug this into the formula and we get

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°