Solve this system of linear equations by graphing: 3y+4x=3
x+3y=-6
I sort of already solved it. I used standard form. (The one where you have a table and do x intercept and y intercept. For y int, x=0 and for x int, y=0) Ax=By=C
I got x=3/4 and y=1; for the second one, I got x=-6 and y=2. What did I do wrong?

whats the answer choices

Step-by-step explanation:

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.