Mathematics, 03.12.2020 04:00, trobbie817

J(x) = x^2 – 2x + 5 and
k(x) = 4x^2 – 3
j(-4) – k(5)

Answers: 2

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J(x) = x^2 – 2x + 5 and
k(x) = 4x^2 – 3
j(-4) – k(5)...

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J(x) = x^2 – 2x + 5 and k(x) = 4x^2 – 3 j(-4) – k(5)

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J(x) = x^2 – 2x + 5 and
k(x) = 4x^2 – 3
j(-4) – k(5)