β
1
2
β
2
+
1
8
=
0
Combine multiplied terms into a single fraction
β
1
2
2
+
1
8
=
0
β
1
2
2
+
1
8
=
0
Multiply all terms by the same value to eliminate fraction denominators
β
1
2
2
+
1
8
=
0
2
(
β
1
2
2
+
1
8
)
=
2
β
0
Simplify
Distribute
2
(
β
1
2
2
+
1
8
)
=
2
β
0
2
(
β
1
n
2
2
+
18
)
=
2
β
0
2(2β1n2β+18)=2β
0
2
β
β
1
2
2
+
3
6
=
2
β
0
2
β
β
1
n
2
2
+
36
=
2
β
0
2β
2β1n2β+36=2β
0
Cancel multiplied terms that are in the denominator
2
β
β
1
2
2
+
3
6
=
2
β
0
2
β
β
1
n
2
2
+
36
=
2
β
0
2ββ
2ββ1n2β+36=2β
0
β
1
2
+
3
6
=
2
β
0
Multiply by zero
β
1
2
+
3
6
=
2
β
0
β
1
n
2
+
36
=
2
β
0
β1n2+36=2β
0
β
1
2
+
3
6
=
0
β
1
n
2
+
36
=
0
β1n2+36=0
β
1
2
+
3
6
=
0
=
β
Β±
2
β
4
β
2
n
=
β
b
Β±
b
2
β
4
a
c
2
a
n=2aβbΒ±b2β4acββ
Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.
β
1
2
+
3
6
=
0
β
1
n
2
+
36
=
0
β1n2+36=0
=
β
1
a
=
β
1
a=β1
=
0
b
=
0
b=0
=
3
6
c
=
36
c=36
=
β
0
Β±
0
2
β
4
(
β
1
)
β
3
6
β
2
(
β
1
)
Simplify
Evaluate the exponent
=
0
Β±
0
2
β
4
(
β
1
)
β
3
6
β
2
(
β
1
)
n
=
0
Β±
0
2
β
4
(
β
1
)
β
36
2
(
β
1
)
n=2(β1)0Β±02β4(β1)β
36ββ
=
0
Β±
0
β
4
(
β
1
)
β
3
6
β
2
(
β
1
)
Multiply the numbers
=
0
Β±
0
β
4
(
β
1
)
β
3
6
β
2
(
β
1
)
n
=
0
Β±
0
β
4
(
β
1
)
β
36
2
(
β
1
)
n=2(β1)0Β±0β4(β1)β
36ββ
=
0
Β±
0
+
1
4
4
β
2
(
β
1
)
Add the numbers
=
0
Β±
0
+
1
4
4
β
2
(
β
1
)
n
=
0
Β±
0
+
144
2
(
β
1
)
n=2(β1)0Β±0+144ββ
=
0
Β±
1
4
4
β
2
(
β
1
)
Evaluate the square root
=
0
Β±
1
4
4
β
2
(
β
1
)
n
=
0
Β±
144
2
(
β
1
)
n=2(β1)0Β±144ββ
=
0
Β±
1
2
2
(
β
1
)
Multiply the numbers
=
0
Β±
1
2
2
(
β
1
)
n
=
0
Β±
12
2
(
β
1
)
n=2(β1)0Β±12β
=
0
Β±
1
2
β
2
n
=
0
Β±
12
β
2
n=β20Β±12β
=
0
Β±
1
2
β
2
Separate the equations
To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus.
=
0
+
1
2
β
2
=
0
β
1
2
β
2
Solve
Rearrange and isolate the variable to find each solution
=
β
6
=
6
Solution
=
β
6
=
6
Hope it helps u:) ps have a great day (taken from Google)