1. Graham is hiking at an altitude of 14,040 feet and is descending 50 feet each minute. Max is
hiking at an altitude of 12,500 feet and is
ascending 20 feet each minute. How many
minutes will it take Graham and Max to meet at
the same altitude ?
a. Equation:
1
2
. Solution:
2. At what altitude will Graham and Max meet?
3

 Equation 1 to find the time: A₁ - r₁t = A₂ + r₂t  Solve for t

14040 - 50t = 12500 + 20t     t is the number of minutes

Equation 2 to find the altitude: A₁ - r₁t = A₂ + r₂t  A₁ and r₁ are Grahams initial altitude and rate. Use given rates, calculated time and solve for A.

A₂ and r₂ are Max's initial altitude and rate.

They will meet in 22 minutes

They will meet at 12940 ft altitude

Step-by-step explanation:  Their original heights plus/minus the altitude change per minute (rate) and the time will be equal when they meet.

14040 - 50t = 12500 + 20t    subtract 12500 from both sides; add 50t to both sides.

14040-12500 = 20t + 50t

1540 = 70x

22 = t  They will meet in 22 minutes.  

To get the altitude where they meet, Multiply the time by the rate for each climber. Add or subtract per equation: A₁ - r₁t = A₂ + r₂t

14040 - 22(50) = 12500 + 22(20)

Graham: 22 min × 50ft/min = 1100 ft

Subtract from his starting altitude:

14040 - 1100 = 12940 ft

Max: 22 min ×20 ft/min = 440 ft

Add to his starting altitude

12500 + 440 = 12940 ft

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)

you didn't give me the choices, so i will just give you the graph so you can look at your choices and choose the right one.