Help me please solve this

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  a) no

  b) yes

Step-by-step explanation:

a) You cannot draw the graph around x=0 without lifting your pencil. The function is not continuous at x=0.

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b) You can draw the graph around x=1 without lifting your pencil. The function is continuous at x=1.

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Additional comment

In technical terms, the limit from the left at x=0 is 2; the limit from the right is 3. These are different, so the function is not continuous there.

On the other hand, the left and right limits at x=1 are the same (both 2), and are equal to the value of the function at that point (f(1)=2). Hence, the function is continuous at x=1.

the two may have that, even a breakdown is probably offered

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step-by-step explanation: