The sum of triple a number and four is no more than fourteen and no less than 5 Write the statement into an inequality
(ASAP)

let n be the number

then the sum of this number and 7 is

n

+

7

and 3 times this sum is

3

(

n

+

7

)

5 times the number less thirteen is

5

n

−

13

⇒

3

(

n

+

7

)

>

5

n

−

13

←

is the inequality

distribute the brackets on the left side

3

n

+

21

>

5

n

−

13

subtract 3n from both sides

3

n

−

3

n

+

21

>

5

n

−

3

n

−

13

⇒

21

>

2

n

−

13

add 13 to both sides

21

+

13

>

2

n

−

13

+

13

⇒

34

>

2

n

divide both sides by 2

17

>

n

⇒

n

<

17

Step-by-step explanation:

may i see the picture? it would a lot, xox

answer: i think it is c