A train leaves the station at time = 0. Traveling at a constant speed, the train travels 330 kilometers in 3 hours. Answers parts a and b. A. Write a function that relates the distance traveled d to time t. The function that relates the distance traveled d to the time is.

The function that relates the distance traveled d to the time t is

f(t) = 110t, where d = f(t)

Step-by-step explanation:

From the question, we were told that the train is At a constant speed, the train travels 330 kilometers in 3 hours

We were told to write function that relates the distance traveled d to the time t, we can do this by writing a linear equation with those functions

Since we are told that the train travels 330 kilometers in 3 hours, then we can say the train travel (330/3) kilometers in 1 hour which means it travel 110 kilometers in 1 hour

Then d= 110teqn(1)

If if t = 0, then d = 0, as well since at t=0 the train is at the station

At t = 1 then d = 110.

From equation (1) d can be replaced by f(t) then we have

f(t) = 110teqn(2)

Now we replace d by f (t), because d = f t):

f(t) = 120t

Therefore, The function that relates the distance traveled d to the time is f(t) = 120t

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!