For this question, use the 68-95-99.7 rule. A researcher has a colony of bongo spiders in his lab. There are 1200 adult spiders in the colony, and their weights are normally distributed with a mean of 11 grams and a standard deviation of 2 grams. a. Sketch a normal curve and label the axis using the mean and standard deviation. Be sure to label one, two, and three standard deviations on either side of the mean. b. Using the 68-95-99.7 rule, about what percent of spiders in the colony weigh between 7 grams and 13 grams? c. Using the 68-95-99.7 rule, about what percent of spiders in the colony weigh less than 9 grams? d. Approximately 68% of all the spider weights would occur between what two weight values? e. What is the z-score of a spider in this colony that weighs 15 grams? f. What percent of spiders in the colony weigh more than 15 grams?

if you explain the the question more correctly i might be able to answer this better

step-by-step explanation:

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.

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step-by-step explanation: