A company makes spherical tanks that store chemicals. Their standard model has a diameter of 6 meters, but a customer needs a larger tank whose capacity is 2.5 times the volume of the standard model. What is the approximate diameter of this larger tank? Round to the nearest tenth.

The approximate diameter of the larger tank is 8.10 meters

Step-by-step explanation:

Here, we want to calculate the diameter of the larger tank

The volume of a sphere

V = 4/3 * π * r^3

Let us calculate the volume of the standard model

That will be;

Since diameter is 6 and r = d/2

r = 6/2 = 3 meters

V = 4/3 * π * 3^3 = 36 π m^3

Now, the volume of the larger tank is 2.5 times of this;

The volume of the larger tank is 2.5 * 36 π = 90 π m^3

So we can calculate the radius of this before we calculate its diameter

4/3 * π * r^3 = 90 π

4r^3/3 = 90

r^3 = 270/4

r^3 = 67.5

r = 3x√(67.5)

r = 4.07 m

Diameter here is 2 times this

= 4.07 * 2 = 8.14

step-by-step explanation:

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.