PLS HELP A support wire is needed to help stabilize a telephone pole. If the wire is to be attached at the top of the 30-foot telephone pole and it must be anchored to the ground 40 feet from the base of the telephone pole, what is the length of the support wire?

70 feet

Step-by-step explanation:

idk bruv

We need to find the height upto which the guy wire is connected to the pole which is

x

To find that, we can use a simple trigonometry function

If you know a little trigonometry, you can say that,

sin

(

θ

)

=

Opposite

Hypotenuse

The opposite side of

60

∘

is

x

. And the hypotenuse is

40

So,

→

sin

(

60

∘

)

=

x

40

Using the unit circle, we can find that

→

√

2

2

=

x

40

→

x

=

√

2

2

1

⋅

40

20

⇒

x

=

20

√

2

ft

Hope this helps... :)

If you have any doubts, you can ask me at the commennts section.

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Step-by-step explanation:

b is the answer that makes most sense

step-by-step explanation:

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841