Solve 6.1−0.3≥c+1.
please help me

4.8≥c

Step-by-step explanation:

6.1−0.3≥c+1.

5.8≥c+1

4.8≥c

c≤  24/25

Step-by-step explanation:

"0.3" was replaced by "(3/10)". 2 more similar replacement(s). Simplify 3/10

    61     3      

 (—— -  ——) -  (c + 1)  ≥ 0    then simplify 61/10

  10    10    

3.1       Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

    61 - (3)                   29

————————  =  ——

     10                          5

29    

 —— -  (c + 1)  ≥ 0  

 5    

4.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  5  as the denominator :

            c + 1     (c + 1) • 5

   c + 1 =  —————  =  ———————————

              1            5      

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Rewrite the whole as a fraction using  5  as the denominator :

                         c + 1     (c + 1) • 5

   c + 1 =  —————  =  ———————————

                             1            5    

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

                              29 - ((c+1) • 5)     24 - 5c

————————————————  =  ———————

                                          5                5

    24 - 5c

 ———————  ≥ 0  

      5    

Multiply both sides by  5  

5.2    Multiply both sides by (-1)

Flip the inequality sign since you are multiplying by a negative number

     5c-24  ≤ 0

5.3    Divide both sides by  5  

     c-(24/5)  ≤ 0

5.4      Add  24/5  to both sides

            c ≤ 24/5

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is symmetric about the line y = 120,000.

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.