Subtract -2x^2+4x-1−2x 2 +4x−1minus, 2, x, squared, plus, 4, x, minus, 1 from 6x^2+3x-96x 2 +3x−96, x, squared, plus, 3, x, minus, 9.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

12 cups   is the answer

step-by-step explanation:

c. product line extension.

answer: 1400

step-by-step explanation: 20 x 5 = 100 add the zero 1000 8 x 50 = 400 + 1000 = 1400